Autoionization of Water
Core Concept
Autoionization (or self-ionization) of water is a reaction in which two water molecules interact to produce a hydronium ion (H3O+) and a hydroxide ion (OH−).
Reaction: 2H2O(l)⇌H3O+(aq)+OH−(aq)
Alternatively: H2O(l)⇌H+(aq)+OH−(aq)
This equilibrium is fundamental to the pH scale and acid-base chemistry.
Always convert minutes or hours to seconds before multiplying by current.
Water is Always Ionized: Even pure water contains $H_3O^+$ and $OH^-$ due to autoionization.
pH and Kw: The pH scale is derived from the autoionization of water, with $K_w$ determining the relationship between [$H_3O^+$] and [$OH^-$].
Neutrality is Temperature-Dependent: At higher temperatures, water is neutral at a pH lower than 7 because $K_w$ increases.
Test Yourself
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Calculations Involving Kw
Calculating Ion Concentrations
Example: In pure water at 25°C, calculate the concentrations of $H_3O^+$ and $OH^-$.
Given: $K_w = [H_3O^+][OH^-] = 1.0 \times 10^{-14}$
Since $[H_3O^+] = [OH^-]$, let x = [$H_3O^+$]: 2x = $1.0 \times 10^{-14}$
$x = [H_3O^+] = [OH^-] = 1.0 \times 10^{-7} \, \text{M}$
Non-Neutral Solutions
For a solution with $[H_3O^+] = 1.0 \times 10^{-3} \, \text{M}$:
$[OH^-] = \frac{K_w}{[H_3O^+]} = \frac{1.0 \times 10^{-14}}{1.0 \times 10^{-3}} = 1.0 \times 10^{-11} \, \text{M}$
Key Concepts
Equilibrium Constant ($K_w$)
The equilibrium constant for the autoionization of water is denoted as $K_w$.
At 25°C: $K_w = [H_3O^+][OH^-] = 1.0 \times 10^{-14}$
This value varies with temperature, increasing as the temperature rises.
Neutrality of Water
In pure water at $25^\circ\text{C}$: $[\text{H}_3\text{O}^+] = [\text{OH}^-] = 1.0 \times 10^{-7} \, \text{M}$.
The solution is neutral because the concentrations of $\text{H}_3\text{O}^+$ and $\text{OH}^-$ are equal.
Temperature Dependence
The autoionization constant $K_w$ increases with temperature, meaning water becomes slightly more ionized at higher temperatures.
At $50^\circ\text{C}$, $K_w > 1.0 \times 10^{-14}$.